Question

find the least number which on division by 28,42 and 70 leaves a remainder 10 in each case​

Answer 1

Answer:

= (28-10),(42-10),(70-10)

= 18,32,60

= LCM of 18,32&60

= 18=2*3^2

=32=2^5

= 60=2^2*3*5

LCM=2^5*3*5=480

Therefore 480 is the required number.

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