Find the least number which should be added to 2497 so that the sum is exactly divisible by 5,6,4and 3
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Answer :- Any number that can be divided by a, b, c and d is always a multiple of LCM(a, b, c, d)
LCM(3, 4, 5, 6)= 60
Now find the four digit no. multiple of 60 which is > 2497
For that we first divide 2497 with 60 to get the least no. greater than 2497 which is divisible by 3, 4, 5, 6.
So, 2497/60
= 41.6166
= 42 approx.
Therefore the 4 digit no. multiple of 60 (>2497) would be 60 x 42 = 2520
Let the required no. be X
so the equation would be:
X + 2497 =2520
Or, X = 2520 - 2497
Or, X = 23.
Hence, the least no. which should be added to 2497 and divisible by 3, 4, 5 and 6 is 23.
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