Math, asked by kumaranand20091, 8 months ago

Find the least number which should be added to 2497 so that the sum is exactly divisible by 5,6,4and 3​

Answers

Answered by aryanchibber123
7

Answer :- Any number that can be divided by a, b, c and d is always a multiple of LCM(a, b, c, d)

LCM(3, 4, 5, 6)= 60

Now find the four digit no. multiple of 60 which is > 2497

For that we first divide 2497 with 60 to get the least no. greater than 2497 which is divisible by 3, 4, 5, 6.

So, 2497/60

= 41.6166

= 42 approx.

Therefore the 4 digit no. multiple of 60 (>2497) would be 60 x 42 = 2520

Let the required no. be X

so the equation would be:

X + 2497 =2520

Or, X = 2520 - 2497

Or, X = 23.

Hence, the least no. which should be added to 2497 and divisible by 3, 4, 5 and 6 is 23.

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Answered by shaider
0

Answer:

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Step-by-step explanation:

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