Question

Find the least number which should be added to 4100 to get a perfect square. also find the square root of the perfect.
STEP BY STEP SOLUTION.
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Answer 1

Answer:

Step-by-step explanation:

6412

∣80

8∣  

64

ˉ

 

12

ˉ

 

​  

 

∣−64

160∣012

​  

 

∣−00

∣12

​  

 

Since remainder =12

⇒80  

2

<6412<81  

2

 

∴ Required number to be added to make it a perfect square is

81  

2

−6412=6561−6412=149

∴6412+149=6561

and  

6561

​  

=81.

Answer 2

Answer:

$\mathbf{\color{purple}{\huge{✮}}}\mathbf{\blue{\huge{A}}}\mathbf{\color{aqua}{\huge{N}}}\mathbf{\green{\huge{S}}}\mathbf{\color{yellow}{\huge{W}}}\mathbf{\orange{\huge{E}}}\mathbf{\red{\huge{R}}}\mathbf{\color{maroon}{\huge{✮}}}$

First do prime fraction of 273584. Then make pair of 2 ( same number ) . Then add the number which did not come in pair to the original number.

992

273584+992=274576

root 274576 = 524

524^2= 274576 = Answer

$\huge{\underline{\boxed{\purple{{★ Hence \: Verified ★}}}}}$