Question

find the least number which when decided by 10 and leaves 6 as the remainder in each case​

Answer 1

Answer:

Here is your answer⬇️⬇️

First we will find the LCM of 6, 10, 15, 30

6 = 2 × 3

10 = 2 × 5

15 = 3 × 5

30 = 3 × 2 × 5

LCM = 30

Now,

30 + 3 = 33

So, the least number is 33.