Question

Find the least number which when decreased by two is exactly divisible by 18, 45, and 63

with step by step explanation

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Answer 1

Answer:

no number is there

Step-by-step explanation:

bcoz 45-2 =43 and 43 is prime no. hence no number is divisible..

Answer 2

Answer:

Let the number which when decreased by 2 will be divisible by 18,45 and 630 be x

lcm of 18, 45 and 63 = 630

$\frac{x}{630} = 1$

$x = 630$

hence the required number which when decreased by 2 is exactly divisible by 18, 45 and 63 is 630