Find the least number which when devided by 35 56 and 91 leave the same reminder 7 in each case
ayush2883:
no sorry , lcm is 3640 and answer is 3640+7 =3647
Answers
Answered by
3
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Sol:
The smallest number which when divided by 35, 56 and 91 = LCM of 35, 56 and 91
35 = 5 x 7
56 = 2 x 2 x 2 x 7
91 = 7 x 13
LCM = 7 x 5 x 2 x 2 x 2 x 13 = 3640
The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647.
Sol:
The smallest number which when divided by 35, 56 and 91 = LCM of 35, 56 and 91
35 = 5 x 7
56 = 2 x 2 x 2 x 7
91 = 7 x 13
LCM = 7 x 5 x 2 x 2 x 2 x 13 = 3640
The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647.
Answered by
1
lcm of 35,56,91 is 840. 840+7=847 answer
no, the lcm of 35 ,36, 91 ,15 is 3640. and your answer is 3640+7=3647
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