find the least number which when devided by 6,15and 18 leave the reaminder 5 in each case
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Find the least number which when divided by 6, 15 and 18, leave remainder 5 in each case.
Solution
L.C.M of 6, 15 and 18 = 2 x 3 x 3 x 5 = 90
Therefore the required number = 90+5=95.
Hence, 95 is the answer.
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Find the least number which when divided by 6, 15 and 18, leave remainder 5 in each case.
Solution
L.C.M of 6, 15 and 18 = 2 x 3 x 3 x 5 = 90
Therefore the required number = 90+5=95.
Hence, 95 is the answer.
Please mark it as brainliest answer and don't forget to follow me.
AritraRoy6543:
thank u
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