Find the least number which when devided by 96 and 128 leaves a remainder 10 in each case.
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Firstly find the lcm of 96 and 128
It is lcm(96,128)= 384
For having 10 as the remainder, add 10 to 384.
So 384+10=394.
394 is the required answer.
Cheers. Mark brainliest please.
Hope it helps u. ;-)
It is lcm(96,128)= 384
For having 10 as the remainder, add 10 to 384.
So 384+10=394.
394 is the required answer.
Cheers. Mark brainliest please.
Hope it helps u. ;-)
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