Question

Find the least number which when dided by 6, 15 and 18
leave remainder 7 in each case​

Answer 1

Step-by-step explanation:

Firstly we need to find the LCM of the numbers

LCM of 6,15,18 is 90

In case of 6 there won't be remainder 7. Remainder that are possible are 1,2,3,4,5

So the question cannot be solved.

90 is the least number which when divisible by 6,15,18 leaves remainder 0

Similarly,

91 is the least number which when divisible by 6,15,18 leaves remainder 1

And for remainder 7

97 is the least number which when divisible by 6,15,18 leaves remainder 1 when divided by 6 and remainder 7 when divided by 15,18

If remainder is greater than the divisor then that remainder can be divided by the divisor

For example, remainder is 8 when divided by 6 will give

Quotient as 1 and remainder 2