Question

Find the least number which when diveded by 6, 15 and 18 leave remainder 5 in each case.​

Answer 1

L.C.M. of 6, 5 and 18

6 = 2*3

15 = 3*5

18 = 2*3*3

L.C.M. of 6, 15 and 18 = 2*3*3*5 = 90

Now,

5 + 90 = 95

Answer 2

To find the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case, we have to find the L.C.M. of 6, 15 and 18 and then add 5 in that number.

Hence, 95 is the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case.