Find the least number which when diveded by 6, 15 and 18 leave remainder 5 in each case.
Answers
Answered by
3
L.C.M. of 6, 5 and 18
6 = 2*3
15 = 3*5
18 = 2*3*3
L.C.M. of 6, 15 and 18 = 2*3*3*5 = 90
Now,
5 + 90 = 95
Answered by
1
To find the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case, we have to find the L.C.M. of 6, 15 and 18 and then add 5 in that number.
Hence, 95 is the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case.
Similar questions