Question

Find the least number which when divide by 15,18 and 25 leaves a remainder 4 in case.

give me the step by step solution plz plz ​

Answer 1

LCM of 15 and 25 is 75.

LCM of 15 and 25 is 75.So the number must be 75m-7 (as 15–8=25–18=7)

LCM of 15 and 25 is 75.So the number must be 75m-7 (as 15–8=25–18=7)where m is an integer.

LCM of 15 and 25 is 75.So the number must be 75m-7 (as 15–8=25–18=7)where m is an integer.Now when we put the values for m, so

LCM of 15 and 25 is 75.So the number must be 75m-7 (as 15–8=25–18=7)where m is an integer.Now when we put the values for m, so75×1–7=68 which is not divisible by 11

LCM of 15 and 25 is 75.So the number must be 75m-7 (as 15–8=25–18=7)where m is an integer.Now when we put the values for m, so75×1–7=68 which is not divisible by 1175×2–7=143 which is divisible by 11.

LCM of 15 and 25 is 75.So the number must be 75m-7 (as 15–8=25–18=7)where m is an integer.Now when we put the values for m, so75×1–7=68 which is not divisible by 1175×2–7=143 which is divisible by 11.Therefore the number when divided by 15 and 25 leaves remainder 8 and 18 respectively and leaves no remainder when divided by 11 is 143.

LCM of 15 and 25 is 75.So the number must be 75m-7 (as 15–8=25–18=7)where m is an integer.Now when we put the values for m, so75×1–7=68 which is not divisible by 1175×2–7=143 which is divisible by 11.Therefore the number when divided by 15 and 25 leaves remainder 8 and 18 respectively and leaves no remainder when divided by 11 is 143.Hope it help…

Answer 2

take the lcm of 15, 18,25

you will get the lcm 450

then add remainder 4

you will get the answer 454