Math, asked by rajiashok3128, 10 months ago

find the least number which when divide by 15 20 and 35 leaves remainder 3 in each case​

Answers

Answered by vanshika2453
0

Answer:

425 is the correct answer as L.C.M. of 15,20 ad 35 is 420. So required no. =420+5=425. Then it leaves remainder 5 in each case.

Answered by ranjanasri2232
0

the smallest number which leaves remainder 5 when divided by 15 ... 425 is the correct answer as L.C.M. of 15,20 ad 35 is 420. So required no. =420+5=425. Then it leaves remainder 5 in each case.

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