Find the least number which when divide by 626, 618 and 676 leaves a remainder 3 in each
case.
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Question :- Find the least number which when divide by 626, 618 and 676 leaves a remainder 3 in each case. ?
Solution :-
The least required number will be :- LCM of (626, 618 and 676) + 3.
Lets first find LCM of given numbers .
Prime Factors of 626, 618 and 676 are :-
→ 626 = 2 * 313
→ 618 = 2 * 3 * 103
→ 676 = 2 * 2 * 13 * 13
So,
→ LCM = 2 * 2 * 3 * 13 * 13 * 103 * 313 = 65,380,692 .
Therefore,
→ Required Number = LCM + 3 = 65,380,692 + 3 = 65,380,695 . (Ans.)
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