Math, asked by mihirmishra22, 8 months ago



Find the least number which when divide by 626, 618 and 676 leaves a remainder 3 in each
case.​

Answers

Answered by RvChaudharY50
8

Question :- Find the least number which when divide by 626, 618 and 676 leaves a remainder 3 in each case. ?

Solution :-

The least required number will be :- LCM of (626, 618 and 676) + 3.

Lets first find LCM of given numbers .

Prime Factors of 626, 618 and 676 are :-

→ 626 = 2 * 313

→ 618 = 2 * 3 * 103

→ 676 = 2 * 2 * 13 * 13

So,

LCM = 2 * 2 * 3 * 13 * 13 * 103 * 313 = 65,380,692 .

Therefore,

Required Number = LCM + 3 = 65,380,692 + 3 = 65,380,695 . (Ans.)

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Answered by sushmasharma89271750
0

find the last number which

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