Math, asked by Salil173, 1 year ago

Find the least number which when divide by 8,14,20,25 and leaves 4 as remainder in each case​

Answers

Answered by tannapriyam
3

I don't know about 8 but

of 14 is 2 because 2×5 =10 and 14 -10 =4

of 20 is 8 because 8×2=16and 20-16=4

of 25 is 3


Salil173: no u are wrong simple ans is that take the LCM of all the numbers and then add 4 to the LCM then the num which comes after adding 4 to the LCM is the answer
tannapriyam: but according to your condition it satisfies it
Salil173: i think u did,nt understand. the wue
Salil173: i mean question
Answered by pinquancaro
14

The least number which when divide by 8,14,20,25 and leaves 4 as remainder in each case is 1404.

Step-by-step explanation:

To find : The least number which when divide by 8,14,20,25 and leaves 4 as remainder in each case?  

Solution :  

We find the LCM of 8,14,20,25,

2 | 8  14  20  25

2 | 4   7   10  25

2 | 2   7    5   25

5 |  1    7    5   25

5 |  1    7    1    5

7 |  1    7    1    1

  | 1      1    1      1

LCM(8,14,20,25)=2\times 2\times 2\times 5\times 5\times 7  

LCM(9,13)=1400  

In each case it leaves a remainder 4 so we add 4 in the LCM of the numbers.

i.e. 1400+4=1404.

Therefore, The least number which when divide by 8,14,20,25 and leaves 4 as remainder in each case is 1404.

#Learn more

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