Question

find the least number which when divided 12, 16 and 24 leaves a remainder 5 in each case​

Answer 1

Answer:

Step-by-step explanation:

LCM of 12 = 2 * 2 * 3

LCM of 16 = 2 * 2 * 2 * 2

LCM of 24 = 2 * 2 * 2 * 3

LCM of 12,16,24 = 48

Least number when leaves remainder 7 is = 48 + 7

                                                                       = 55

Answer 2

Answer:

I think so first we have to find the HCF of the given numbers 1216and24 which will be by common division because only with common division we get a remainder and u get the answer whivh will be the HCF I do not know if it is correct but yeah I hope this helps u a bit