Find the least number which when
divided by 10,14 and 18 leaves 4 as
the remainder in each case
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2
Answer: 2
Step-by-step explanation:
First subtract 10, 14 and 18 by 4 to get the answer.
Then, Find the Hcf of 6, 10 and 14 by Euclid's Division Lemma
Hcf(6,10,14)= 2
Therefore, The least number which when divided by 10, 14 and 18 leaves 4 as remainder= 2
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