Math, asked by reetabhoomikadaiwik, 10 months ago

find the least number which when divided by 10 , 15 , 20 leaves a remainder 4 in each case .

Answers

Answered by ayushyadav143
5

Your answer is given below *****

Step-by-step explanation:

Given numbers are 12 , 15 , 20 , 54

To Find: least no. which is divided by given nos. and leaves remainder 8

Least no which is divisible by all given no is LCM of all nos.

LCM means least common multiple.

First we find LCM of 12 , 15 , 20 , 54 by prime factorization method

12 = 2 × 2 × 3

15 = 3 × 5

20 = 2 × 2 × 5

54 = 2 × 3 × 3 × 3

LCM( 12, 15 , 20 , 54 ) = 2 × 2 × 3 × 3 × 3 × 5 = 540

To find the required no. we add 8 to LCM

⇒ Required No. = 540 + 8 = 548

Thus, 548 is the least no which when divided by 12 15 20 and 54 leaves in each case a remainder of 8.

Answered by akshatbisht344
10

Answer: 64 is the least number divided by 10,15 and 20 and leave remainder 4

Step-by-step explanation: LCM of 10 , 15 and 20 = 60

So , 60 is the least number of divisible by 10 ,15 and 20 .

There should be remainder 4 .

So, we will add 4 to 60 which give us 64 . So, 64 is the least number divided by 10,15 and 20 and leave remainder 4 .

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