Question

Find the least number which when divided by 10, 15 and 20 leaves a remainder 4 in each case​

Answer 1

Answer:

528

Step-by-step explanation:

given x leaves remainder 4 in each case

so, the required no.s are 10 - 4 = 6  ;  15 - 4 = 11  ;  20 - 4 = 16

6 = 2 * 3

11 = 11 * 1

16 = 2 * 2 * 2 * 2

LCM = 2 * 2 * 2 * 2 * 3 * 11 = 528

HOPE IT HELPS!!! :):)