Find the least number which when divided by 12,14,and 18 respectively leaves remainder 5 in each time
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Answer:
257
Step-by-step explanation:
LCM of 12,14 and 18
12 = 2 x 2 x 3 x 1
14 = 2 x 7 x 1
18 = 2 x 3 x 3 x 1
LCM( 12, 14, 18 ) = 2 x 2 x 3 x 3 x 7 = 252
smallest whole number = 252 + 5 = 257
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