Question

find the least number which when divided by 12,15,18 and 20 leaves a remainder of 5 in each case​

Answer 1

Answer:

185

Step-by-step explanation:

L.C.M of 12, 15, 18, 20 is 180

therefore , asked no. is L.C.M + 5

ANS. 185

Answer 2

Given:

The least number which when divided by 12 , 15 , 18 and 20 leaves a remainder of 5 in each case​.

To find:

The least number which when divided by 12 , 15 , 18 and 20 leaves a remainder of 5 in each case​.

Solution:

We can find the least number which when divided by 12 , 15 , 18 and 20 leaves a remainder of 5 in each case​ by finding the LCM of 12 , 15 , 18 and 20

LCM of 12 , 15 , 18 and 20 using prime factorization method.

12 = 2 × 2 × 3

15 = 3 × 5

18 = 2 × 3 × 3

18 = 2 × 2 × 5

LCM of 12 , 15 , 18 and 20 is 2 × 2 × 3 ×  3 × 5

LCM of 12 , 15 , 18 and 20 is 180

Then add the remainder value to the LCM = 180 + 5

The required number is 185

The least number which when divided by 12 , 15 , 18 and 20 leaves a remainder of 5 in each case​ is 185

Final answer:

The least number which when divided by 12 , 15 , 18 and 20 leaves a remainder of 5 in each case​ is 185