find the least number which when divided by 12 , 15 , 20 and 54 leaves a remainder 8
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Answered by
2
Answer:
548
548 is the least no which when divided by 12 15 20 and 54 leaves in each case a remainder of 8.
Answered by
2
Answer:
548
Step-by-step explanation:
LCM of 12, 15, 20, 54
12= 2 x 2 x 3
15= 3 x 5
20 = 2 x 2 x 5
54=2 x 3x3x3
LCM = 27 x 4 x 5 = 27 x 20
= 540
ADD 8
= 540 + 8 548
Therefore, the answer is 548
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