Question

find the least number which when divided by 12,15,36 and 45 leaves in each case remainder 4

Answer 1

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Answer 2

Answer:

Step-by-step explanation:

Concept :

The concept of LCM will be used to solve this question.

Given :

The given numbers are $12,15,36$ and $45$ which will divide the number and the remainder is $4$ .

To Find:

We have to find the number which will be divided by $12,15,36$ and $45$ and in each case remainder $4$ .

The LCM of  $12,15,36$ and $45$ is $2 \times 2 \times 3 \times 3 \times 5 =180$  .

$4$ will be remainder in each case.

So, $4$ will be added with $180$ .

Therefore, the least number is $180+4=184$ .

$184$ is the least number that is divided by $12,15,36$ and $45$ leaves in each case remainder $4$ .

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