Find the least number which when divided by
12, 16, 14 and 36 leaves a remainder 7 in each case
Answers
Answered by
20
Answer:
The smallest number which divides 12,16,24 and 36 is 144. But we have a condition that it leaves a remainder of 7. So we add 7 to the LCM (144+7=151). Hence the smallest number that when divided by 12 16 24 and 36 leaves a remainder 7 is 151.
Answered by
0
Answer:
151 is the least number which when divided by
12, 16, 14 and 36 leaves a remainder 7 in each case
Similar questions