Question

Find the least number which when divided by 12,16,24,36 leaves a remainder 7 in each case? ​

Answer 1

Answer:

The least number which when divided by 12,16,24 and 36 leaves a remainder 7 in each case IS 151

Step-by-step explanation:

First we have to find the L.C.M of 12,16,24,36

L.C.M by prime factorization method

12= 2*2*3

16=2*2*2*2

24= 2*2*2*3

36= 2*2*3*3

L.C.M= 2*2*2*2*3*3 = 144

Add remainder 7 to the L.C.M = 144+7= 151

Answer 2

Answer:

the least number is 151

Step-by-step explanation:

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