find the least number which when divided by 12,16,24,36 leaves the remainder 5 in each case
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Answered by
1
Answer:
The smallest number which divides 12 16 24 and 36 is 144. But we have a condition that it leaves a remainder of 7. So we add 7 to the LCM (144+7=151). Hence the smallest number that when divided by 12 16 24 and 36 leaves a remainder 7 is 151.
Step-by-step explanation:
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Answered by
2
Answer:
149
Step-by-step explanation:
The LCM which divides 12 16 24 and 36 is 144.
Remainder = 5.
Add 5 to the LCM (144+5=149).
Hence the smallest number that when divided by 12 16 24 and 36 leaves a remainder 5 = 149
Im not sure
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