Find the least number which when divided by 12, 16 ,24 and 36 leaves a remainder 7 in each case. *
141
131
133
151
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2
Answer:
The smallest number which divides 12 16 24 and 36 is 144. But we have a condition that it leaves a remainder of 7. So we add 7 to the LCM (144+7=151). Hence the smallest number that when divided by 12 16 24 and 36 leaves a remainder 7 is 151.
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