Find the least number which when divided by 12, 27 and 35 leaves 6 as a reminder?
Answers
Find the least number which when divided by 12, 27 and 35 leaves 6 as a remainder?
Answer :- 3774. 3780.
Given: Three numbers 12, 27 and 35
To find: The least number which when divided by given numbers, leaves remainder 6
Solution: To find the required number, first we need to find the least number which is exactly divisible by 12, 27 and 35 which is their LCM.
Using prime factorization method:
12 = 2 × 2 × 3
27 = 3 × 3 × 3
35 = 5 × 7
LCM is the product of maximum frequencies of all the factors of given numbers.
LCM = 2 × 2 × 3 × 3 × 3 × 5 × 7 = 3780
So, 3780 is the least number which is exactly divisible by the given numbers.
Th required number will be 3780 + 6 i.e., 3786.
Hence, the least number which when divided by 12, 27 and 35 leaves remainder 6 is 3786.