Math, asked by Takchsheel, 7 months ago

Find the least number which when divided by 12,30 and 36 leave remainders 10 in each case.​

Answers

Answered by jobansandhu83744
2

Answer:

Take L.C.M of 12 , 30 and 36

12 = 2×2×3

30= 2×3×5

36 =2×2×3×3

so, their LCM is 2×2×3×2×3×5×2×2×3×3 =180

Add 10 in L.C.M =180+10 = 190

so ,the least number which when divided by 12, 30 and 36 leaves remainder 10 in each case is 190.....

Similar questions