Find the least number which when divided by 12,30 and 36 leave remainders 10 in each case.
Answers
Answered by
2
Answer:
Take L.C.M of 12 , 30 and 36
12 = 2×2×3
30= 2×3×5
36 =2×2×3×3
so, their LCM is 2×2×3×2×3×5×2×2×3×3 =180
Add 10 in L.C.M =180+10 = 190
so ,the least number which when divided by 12, 30 and 36 leaves remainder 10 in each case is 190.....
Similar questions