find the least number which when divided by 12,8,and 10 leaves the remainders 10,6,8 respectively
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Let x be a smallest number which on dividing by 6,8 and 12 leaves the remainder 4,6 and 10 respectively. Hence, 142 is the smallest number which on dividing by 6,8 and 12 leaves remainder 4,6 and 10 respectively.21-Dec-2017
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