Question

Find the least number, which when divided by 12 leaves a remainder 10, when
divided by 18 a remainder 16 and when divided by 32 a remainder 30​

Answer 1

Answer:

286

Step-by-step explanation:

LCM(12,18,32) =288

Now, the number has a remainder of 10 when divided by 12. Similarly, number has remainder 16 on dividing by 18 and remainder is 30 when divided by 32. In each case, we are 2 short of getting a zero remainder. So the desired number must be 288−2=286