Question

Find the least number which when divided by 13, 9 and 15 leaves the remainders 8, 4 and 10.
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Answer 1

Answer:

LCM of the numbers 15, 25 and 35 will be 7 5 ∗ 7 = 5 2 5 Now, number has a remainder of 25 when divided by 35. Similarly, number has remainder 15 on dividing by 25 and remainder is 5 when divided by 15. In each case, we are 10 short of getting a zero remainder. So the desired number must be 5 2 5 − 1 0 = 5 1 5

Step-by-step explanation: