Find the least number which when divided by 15, 18 and 25 leaves a remainder 2 in each case.
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Answered by
0
Answer:
6 = 2 × 3
15 = 3 × 5
18 = 2 × 3 × 3
L.C.M of 6, 15 and 18 = 2 x 3 x 3 x 5
L.C.M (6, 15 and 18) = 90
Therefore, the required number = 90+5 = 95
As a result, 95 is the smallest number, with a remainder of 5 in each case when divided by 6, 15, and 18.
Answered by
0
Answer: 452
Step-by-step explanation:
least number = LCM
So first find the lcm of all the three numbers(15, 18,25)
LCM=450
next the remainder should be 2 so we need to add 2 to the LCM.
the LCM is divisible by all the numbers and if we add 2 then it will the extra remainder.
refer to the image attached.
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