Question

Find the least number which when divided by 15,20 and 24 will leave a remainder of 7 in each case

Answer 1

Answer:

Step-by-step explanation:

It has to be 7 more than a multiple of each, hence 7 more than a multiple of their LCM. In fact, 7 + the LCM is the least number that works:

15 = 3 * 5 ;

20 = 2^2 * 5 ; and

24 = 2^2 * 3 ;

So the LCM is 2^3 * 3 * 5 = 120 .

So the number that we want is 127 .

Answer 2

Answer:

Step-by-step explanation:

First find the LCM of the 3 numbers than add 7 to your answer.

LCM = 120

120 + 7 = 127