Math, asked by manjukumari5january1, 9 months ago

Find the least number which when divided by 15 20 and 48 leaves a remainder 9 in each case

Answers

Answered by rs9916948

4

Answer:

The answer is 249. 249 divided by 15 or 20 or 48 leaves a remainder of 9 in each case.

Answered by agarwalshubh092

1

Answer:

the answer is 24 9.20 49 divided / 15 or 20 aur 48 liver reminder 9 in each case

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