Math, asked by siya2009, 5 months ago

Find the least number which when divided by 15, 21 and 18 leaves remainder 3 in each case.

Answers

Answered by goyalvandna01

0

The required number = LCM of (15, 18, 21) – 13 = (3 × 5 × 6 × 7) – 13 = 630 – 13 = 617.

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