Math, asked by wahib2253, 8 months ago

Find the least number which when divided by 15 ,25 ,and 6 leaves remain
der 7 in each case

Answers

Answered by yashrajlegend
2

Answer:

In each case it leaves a remainder 7 so we add 7 in the LCM of the numbers. i.e.1890+7=1897. Therefore, The least number which when divided by 15, 27, 35 and 42 leaves a remainder 7 in each case is 1897.

Step-by-step explanation:

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