FIND THE LEAST NUMBER WHICH WHEN DIVIDED BY 16 18 AND 21LEAVES THE REMINDER 3 5 8 RESPECTIVILY
FIND THE HCF AND LCM OF 48 108 280 1234 5698 123456789
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Answered by
2
Answer:
Step-by-step explanation:
Since, 16 - 3 = 18 - 5 = 21 - 8 = 13
Thus, The least number which when divided by 16,18,21 leaves a remainder 3,5,8
= L.C.M.( 16, 18, 21 ) - 13
Since, 16 = 2 × 2 × 2 × 2
18 = 2 × 3 × 3
21 = 3 × 7
⇒ L.C.M.( 16, 18, 21 ) = 2 × 2 × 2 × 2 × 3 × 3 × 7 = 1008
Hence, The least number which when divided by 16,18,21 leaves a remainder 3,5,8 = 1008 - 13 = 995.
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Answered by
1
Answer:
2522
Step-by-step explanation:
The least multiple of 13, which on dividing by 4, 5, 6, 7 and 8 leaves remainder 2 in each case is : - GKToday. LCM of 4, 5, 6, 7 and 8 = 840. Let require number be 840 K + 2 which is multiple of 13. 3 + 2 = 2520 + 2 = 2522
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