Math, asked by Anonymous, 11 months ago

FIND THE LEAST NUMBER WHICH WHEN DIVIDED BY 16 18 AND 21LEAVES THE REMINDER 3 5 8 RESPECTIVILY

FIND THE HCF AND LCM OF 48 108 280 1234 5698 123456789

Answers

Answered by viswasbkurian77
2

Answer:

Step-by-step explanation:

Since, 16 - 3 = 18 - 5 = 21 - 8 = 13

Thus, The least number which when divided by 16,18,21 leaves a remainder 3,5,8

= L.C.M.( 16, 18, 21 ) - 13

Since, 16 = 2 × 2 × 2 × 2

18 = 2 × 3 × 3

21 = 3 × 7

⇒  L.C.M.( 16, 18, 21 ) = 2 × 2 × 2 × 2 × 3 × 3 × 7 = 1008

Hence, The least number which when divided by 16,18,21 leaves a remainder 3,5,8  = 1008 - 13 = 995.

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Answered by ronaldo7777772
1

Answer:

2522

Step-by-step explanation:

The least multiple of 13, which on dividing by 4, 5, 6, 7 and 8 leaves remainder 2 in each case is : - GKToday. LCM of 4, 5, 6, 7 and 8 = 840. Let require number be 840 K + 2 which is multiple of 13. 3 + 2 = 2520 + 2 = 2522

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