Find the least number which when divided by 16,22 and 40 which when leaves a remainder 7 in each case
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16-7=9
22-7=15
40-7=33
hcf(9,15,33)=3
22-7=15
40-7=33
hcf(9,15,33)=3
worldztopp41pxs:
You're wrong bro
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