Math, asked by ARINDOMDEBBARMA, 11 months ago

find the least number which when divided by 16,24,32,48,60.Leaves remainder 13,21,29,45, and 57 respectively.​

Answers

Answered by MONUKK
0

Answer:

Step-by-step explanation:

The smallest number which when divided by 16, 24, 32, 48 ,60 leaves a remainder of 13, 21, 29, 45 AND 57 respectively is

LCM OF  16,24,32,48,60  = 960

AND NOW

16-3=13

24-3=21

32-3=29

48-3=45

60-3=57

So, (960 - 6 = 954) will have remainder of 13, 21, 29, 45,and 57 when divided by 16, 24, 32, 48,and 60 respectively.

so the answer is 954

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