find the least number which when divided by 16,24,32,48,60.Leaves remainder 13,21,29,45, and 57 respectively.
Answers
Answered by
4
At first find the least no. divisible by 16,24,32,48,60.
Least no. that is divisible by 16,24,32,48,60 = L.C.M of 16,24,32,48,60. L.C.M of 16,24,32,48,60 = 480. SO the least number divisible by 16,24,32,48,60 = 480. Now, As we can see that remainder is always 3 less than corresponding divisors.
i.e 16 - 3 = 13 or 24 - 3 = 21 or 32 - 3 = 29 etc.
Therefore the number will be 480 - 3 = 477.
Least no. that is divisible by 16,24,32,48,60 = L.C.M of 16,24,32,48,60. L.C.M of 16,24,32,48,60 = 480. SO the least number divisible by 16,24,32,48,60 = 480. Now, As we can see that remainder is always 3 less than corresponding divisors.
i.e 16 - 3 = 13 or 24 - 3 = 21 or 32 - 3 = 29 etc.
Therefore the number will be 480 - 3 = 477.
aritramondal1:
M.M.THANKS
Similar questions