Math, asked by garimavaila12, 1 year ago

Find the least number which when divided by 16,28,40 and 77 leaves 8 as a remainder in each case.

Answers

Answered by aryan120ac
5
first subtract 8 from all the no.
then take 1st two no.
12 and 20 (after sub.)
20=12 x 1+ 8
12= 8  x 1+ 4
  8=  4 x 2 +0
HCF=4

then take 3rd no. 
32=4 x 8+ 0
HCF=4

then take 4th no.
69=4 x 17+1
 4 =1 x  4 + 0
hence,the LCM is 1
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