Question

Find the least number which when divided by 16,28,40 and 77 leaving a remainder of 13 in each case

Answer 1

For this particular sum we need to find the LCM of the given numbers.

The smallest number which when divided by 16,28,40 and 77 = LCM of 16,28,40 and 77

16 = 2 × 2 × 2 × 2

28 = 2 × 2 × 7

40 = 2 × 2 × 2 × 5

77 = 7 × 11

LCM = 6160

The smallest number which divides 16,28,40 and 77 is 6160. But we have a condition that it leaves a remainder of 13. So we add 13 to the LCM (6160+13=6173).

Hence the smallest number that when divided by 16,28,40 and 77 leaves a remainder of 13 is 6173.

Answer 2

for This particle Sum we need to find the LCM of the given numbers

the smallest number which when divided by 16,28,40,and77.= 16,28,40,77

16=2×2×2×2

28=2×2×7

40=2×2×2×5

77=7×11

LCM =6160answer