Math, asked by AlphinGame, 1 day ago

Find the least number which when divided by 16, 28 and 40 leaves a
remainder 7 in each case.

Answers

Answered by karnkamal990

0

the smallest number that when divided by 16,28,40 and 77 leaves a remainder of 13 is 6173.

So we add 13 to the LCM (6160+13=6173).

Answered by eldhogeorgy62

1

Answer:

6275

Step-by-step explanation:

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