Find the least number which when divided by 16,36 & 40 leaves 5 as remainder in each case.
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Answer:
725
Step-by-step explanation:
factors of 16,36 and 40 are
16=2^4
36=2^2*3^2
40=2^3*5
so LCM=16,36,40)=2^4*3^2*5
=16*9*5
=720
hence 720 is number divisible by 16,36,40=720
The remainder in all cases =5 so the No=720+5=725
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