Math, asked by enggindustrial09, 7 months ago

Find the least number which when divided by 16 36 and 40 leaves 5 as remainder in each case​

Answers

Answered by Ankit4766
0

Answer:

725

Step-by-step explanation:

Find the LCM of 16, 36 and 40

which is equals to 720

Now add 5, so that o. dividing the remainder comes out to be 5

So, 725 is the least no.

Answered by arindamsur14gmailcom
1

Answer:

THE THE LEAST NUMBER WHICH WHEN DIVIDED BY 16, 36 AND 40 LEAVES 5 AS REMAINDER IN EACH CASE IS 725.

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