Find the least number which when divided by 16,36and 40 leaves 5 as remainderin each case
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725
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☆To slove,
》》Least number which when divided by 16, 16 and 40 leaves 5 as remainder in each case.
☆Solution,
[☆To find the least number we calculate the LCM of the numbers☆]
》》2 | 16,36,40
》》2 | 8,18,20
》》2 | 4,9,10
》》2 | 2,9,5
》》3 | 1,9,5
》》3 | 1,3,5
》》5 | 1,1,5
》》 | 1,1,1
LCM = 2×2×2×2×3×3×5=720
☆Required number=720 + 5 = 725
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