Math, asked by rajeshbhatia467, 9 months ago

Find the least number which when divided by 16,36and 40 leaves 5 as remainderin each case​

Answers

Answered by PokePoke
4

Answer:

725

Step-by-step explanation:

Hope the answer helps you

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Answered by VaibhavTheAryabhatta
2

Answer:

☆To slove,

》》Least number which when divided by 16, 16 and 40 leaves 5 as remainder in each case.

☆Solution,

[☆To find the least number we calculate the LCM of the numbers☆]

》》2 | 16,36,40

》》2 | 8,18,20

》》2 | 4,9,10

》》2 | 2,9,5

》》3 | 1,9,5

》》3 | 1,3,5

》》5 | 1,1,5

》》 | 1,1,1

LCM = 2×2×2×2×3×3×5=720

☆Required number=720 + 5 = 725

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