Question

find the least number which when divided by 18,12 and 24, leaves remainder of 15,9 and 21 respectively​

Answer 1

Answer:

11111111111111111111

Answer 2

Theory :-

When you see the divisors and the remainders, the remainders are exactly

3 less than the divisors.

The easiest of doing this problem is find out the LCM of the three numbers

and reduce it by 3. That will be the smallest number as required by the

question. the LCM will be divisible by all the three numbers and when you

reduce 3 from the LCM the remainder will be three less than the divisors.

Calculation :-

The difference between the divisors and the remainders are same.

i.e., 18 − 15 = 12 − 9 = 24 − 21 = 3

The LCM of (18, 12, 24) − 13 = 2 × 2 × 2 × 3 × 3 − 3 = 72 − 3 = 69

Hence, the correct answer is 69.

Remarks :-

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