Find the least number which when divided by 18 ,21 ,24 and 30 leaves the remainder 9 in each case.
Answers
Answered by
0
First find LCM of 18, 21, 24 and30
Prime factorisation:
18 = 2× 3× 3
21= 3 × 7
24= 2× 2× 2× 3
30= 2× 3× 5
LCM= 3× 3× 2× 2× 2× 5× 7= 2520
Remainder= 9, so number will be = 2520+ 9= 2529
Similar questions