Find the least number which when divided by 18 24 and 32 leaves remainder 7 in each case
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Factor the three numbers: 18, 24, and 32; 3 x 3 x 2, 3 x 2 x 2 x 2, and 2 x 2 x 2 x 2; multiply the factors, 3, 3, 2, 2, 2, 2 gives 288, which is divisible by each of the three numbers with no remainder (quotients: 16, 12, and 9).
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