Math, asked by polukondasnehitha13, 10 months ago


Find the least number which when divided by 2, 3, 4, 5, 6, leaves remainder of 1 in each case
but when divided by 7 leaves no remainder.​

Answers

Answered by hennayeahyea91
2

The required number is 301. Step-by-step explanation: we have to find a number that is divisible by 2,3, 4, 5, and 6 (meaning that it is a multiple of those numbers) and that number + 1 being divisible by 7.

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